4x^2+56x-287=0

Solution for 4x^2+56x-287=0 equation:

4x^2+56x-287=0

a = 4; b = 56; c = -287;
Δ = b2-4ac
Δ = 562-4·4·(-287)
Δ = 7728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7728}=\sqrt{16*483}=\sqrt{16}*\sqrt{483}=4\sqrt{483}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{483}}{2*4}=\frac{-56-4\sqrt{483}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{483}}{2*4}=\frac{-56+4\sqrt{483}}{8}
$